Answer from cs61c-el (David Tung 16479725) for Question 3
There will need to be six wires.  For the first product in the expression, the inputs A and B can be sent directly to an AND gate, and its output gets sent to a wire.  C will need to be sent to a NOT, and its output sent to a wire.  These two wires will be sent to an AND gate to get the value of the first sum.  For the second part, A and C are sent to an AND gate, whose output is sent to a wire.  B inverted is sent to a whle, and AC and !B are sent to an AND gate whose output is a wire.  The wires carrying the values of AB!C and AC!B are then sent to an OR gate, whose value is sent directly to E.