Answer from cs61c-eq (Nicholas Hwang 16732453) for Question 3
6 wires will be needed. AB will run directly into an AND gate which will output into one wire. Then C will run to a NOT gate which will output into a second wire. These two wires will input into a second AND gate which outputs into a third wire. A similar layout expresses the second term for three more wires. Two of the six wires run into the OR gate which outputs E. The inputs and output do not require separate wires, so six will suffice.