Answer from cs61c-ck (Allen Lee 16583554) for Question 4
We can't really tell what $monitor will print to the screen because $monitor is supposed to print something whenever one of its signals changes.  However, in the first initial statement, there is _no_delay_ between the assignments, so a, b, and expected change "simultaneously";  $monitor should print whenever one of its signals changes, so it's undefined what it should print when 3 of its signals change.