Answer from cs61c-ck (Allen Lee 16583554) for Question 1
To find the location in cache that memory location 53 maps to, we must calculate 53 mod 8, which is 5, which is 101 in binary.  Since the cache is eight words, we need log_2(8) = 3 bits for the cache's indexing.  To find the contents of the tag field, we need to find the values of the upper bits of 53:
53 = 2^5 + 2^4 + 2^2 + 2^0 = 110101_two.
The tag field for 53 is 110.